GIVEN:(adsbygoogle = window.adsbygoogle || []).push({});

1. The more accurately you determine a particle's position, the less you know about its momentum, and vice versa. (Heisenberg Uncertainty Principle)

2. Momentum is defined as mass times velocity.

3. Velocity is defined as change in position over time.

4. The rest mass of a particle is definite and non-probabalistic.

5. The increase in mass that occurs to a particle when its velocity increases is also definite and non-probabalistic.

6. Time is quantized- that is, it has a smallest possible unit of duration.

7. Space is also quantized, being time in different clothes. It has a smallest possible unit of length- possibly the Planck length.

Now, suppose you are measuring a the position of a particle of known rest mass as precisely as possible, as often as possible- that is, you are getting it to the nearest space quanta, once per time quanta.

You now have a list of positions, with precise times of occurence for each. You can derive the velocity of the particle, as precisely as is possible, by seeing how much its position changed between each measurement.

From its velocity you can infer its current mass, because you know its rest mass and can calculate how much it's increased from that from the velocity.

Now that you have its velocity and mass, it's a simple matter to calculate its momentum, being the product of the two.

I now have figures that cannot be more precise, for a particle's simultaneous velocity and position- in violation of the Uncertainty Principle.

Either there's a hole in my logic or one or more of my givens is wrong. The first five aren't really in question. Have I disproved the last two, or am I having delusions of grandeur?

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# The Uncertainty Principle and Quantized Time

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