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The Vector Nature of Newton's Second Law

  1. Dec 14, 2004 #1
    A block of mass 2.0kg is placed on a smooth plane, inclined to the horizontal at an angle of 15degrees. The force of gravity, acting straight down on the block, is 20N.
    a) What is the acceleration of the block down the plane?

    I'm having trouble with this because I know:
    Net F=fgcostheta-friction
    or fgcostheta-friction=ma=2a

    BUT THERE IS NO FRICTION GIVEN NOR A COEFFICIENT OF FRICTION

    If anyone knows the answer please share

    THanks
     
    Last edited: Dec 14, 2004
  2. jcsd
  3. Dec 14, 2004 #2
    Of course you don't have a coefficient of friction. A smooth plane implies no friction! Also, the component of the weight acting parallel to the plane is mgsin theta.
     
    Last edited: Dec 14, 2004
  4. Dec 14, 2004 #3
    Ya I'm a real dumbass I also made a 2 other dumb mistakes......i used fgcostheta instead of fgsintheta....THANKS ANYWAY !!!!! grrrrrrrrrrrrrrrrrrrr
     
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