I've got this problem with my HW. Would appreciate the help. Thanks. 1. The problem statement, all variables and given/known data A metal peace with the density of 10,4 g/cm3, has a hole on the inside. The metal weighs 8,2N in air and 7,1N in water. What is the volume of the hole? 2. Relevant equations V = m / ρ m = Fg / g Maybe some else I don't know. 3. The attempt at a solution So I have already managed to figure out that: V1 = (8,2N / 10m/s2) / 10400 kg/m3 = 0,0000788m3 = 78,8cm3; Which means the volume of the metal has to be 78,8cm3, since the hole inside is filled with air and there is air around it. Now I am probably suppose to figure out the volume of the meta peace in the water and then subtract the volume of the metal from it, to get the volume of the hole. But how can I calculate the volume of the metal peace in the water? Help?