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OK. I know I need to use henry's law, s=k*p, but I need some help calculating p, the partial pressure of nitrogen. Then I can use PV=nRT to solve for the volume, right?

TIA.

- Thread starter physicsss
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- #1

- 319

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OK. I know I need to use henry's law, s=k*p, but I need some help calculating p, the partial pressure of nitrogen. Then I can use PV=nRT to solve for the volume, right?

TIA.

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anyone? :-/

- #3

Gokul43201

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As far as I know the equation for solubility is written :

[tex]p = K_c \cdot s~,~ [/tex]

but, from the dimensions you quote for your value of k, your expression (s=k*p) is correct. So, my Kc is 1/k, but that's irrelevant now. Use your expression :

s = k*p

where :

k = 5.8E-7 mol/L-atm

p = partial pressure of nitrogen = 10 atm (I recommend this number, only because of lack of additional information...it may be that you must use 7.8 atm, but I'm not certain)

Plugging these in will give you s. But you know the volume of blood, so . . . . . .

[tex]p = K_c \cdot s~,~ [/tex]

but, from the dimensions you quote for your value of k, your expression (s=k*p) is correct. So, my Kc is 1/k, but that's irrelevant now. Use your expression :

s = k*p

where :

k = 5.8E-7 mol/L-atm

p = partial pressure of nitrogen = 10 atm (I recommend this number, only because of lack of additional information...it may be that you must use 7.8 atm, but I'm not certain)

Plugging these in will give you s. But you know the volume of blood, so . . . . . .

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