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3. The motion of particle of chage q in an electromagnetic field is governed by the Lorentz force (for low velocities v<<c): F=q

**E**+ q

**v**x

**B**.

With both constant

**B**=B

**k**and

**E**=Ey

**j**+ Ez

**K**show that:

z(t)=z(sub-o)+v(sub-zo)t+qE(sub-z)t^2/2m

vx(t)=Asin(omega-t)+E(sub-y)/B

vx(t)=+Acos(omega-t)

I did F=qE+qVxB=m (dv/dt)

dvx/dt= q/m(vyBz)

dvy/dt= q/m(Ey-vxBo)

dvz/dt= q/m (Ez)

I think I'm suppose to now take a second derivative and find the second order differential equation but I'm not too sure how to approach that.