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This is a homework problem for my Introductory Physics(no calculus) class but it's relatively simple so I opted to put it under high school. First I'll state the problem then my thoughts.

A copper rod (k = 390) has a length of 1.5 m and a cross-sectional area of 4.00*10^-4 m^2. One end of the rod is in contact with boiling water and the other with a mixture of water and ice. What is the mass of ice per second that melts? Assume that no heat is lost through the side surface of the rod.

This seems simple enough. Obviously

Q=(390*(4*10^-4)*DT*t)/1.5

DT is where I am coming across a problem. Am I supposed to assume that it is 100-0? Doing so gives

Q=10.4*t J*s

My idea is that in order for the ice to melt it has to have at least m*L (L=33.5*10^4) so I set 10.4*t=m*L

and it follows m/t=10.4/(33.5*10^-4) which is approximately 3.1045*10^-5 kg/s

I would greatly appreciate it if any could help me with this. I can't seem to find much information on this type of problem and I've looked to other books. They seem to have this problem, but no solution.

Anyway, I'm not looking for an answer just trying to see if my logic is correct. Thank you in advance

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# Homework Help: Thermal Conductivity

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