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Can you please help me? I am trying to calculate this equation but can't get correct answer:
Thermal Efficiency, Brake = 1/(bSPC x QHV)
bSPC (brake Specific fuel consumption) = 0.396 kg/KWh
QHV (Heating Value for fuel) = 44 MJ/Kg
The correct answer is meant to be: Thermal Efficiency, Brake = 0.207 = 20.7%.
I do not know the correct SI units for bSPC or QHV, hopefully I am not using the right ones because I can't get that answer.
Look forward to any help or advise, Thanks
Thermal Efficiency, Brake = 1/(bSPC x QHV)
bSPC (brake Specific fuel consumption) = 0.396 kg/KWh
QHV (Heating Value for fuel) = 44 MJ/Kg
The correct answer is meant to be: Thermal Efficiency, Brake = 0.207 = 20.7%.
I do not know the correct SI units for bSPC or QHV, hopefully I am not using the right ones because I can't get that answer.
Look forward to any help or advise, Thanks
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