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- Homework Statement
- How much energy is required to change one quarter of 8.0 kg of water at 25 degrees celsuis into steam(100 degrees celcuis)

- Relevant Equations
- Q=mct

Q=mLv

Q=Qwarm water+Qsteam

Q=mct+mLv

Q=(8kg)(4200J)(100C-25C)+(2kg)(2.3*10 to the power of 6 J/Kg)

Q=7.12*10 to the power of 6 J

Is this the correct answer?

Q=mct+mLv

Q=(8kg)(4200J)(100C-25C)+(2kg)(2.3*10 to the power of 6 J/Kg)

Q=7.12*10 to the power of 6 J

Is this the correct answer?