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Homework Help: Thermal Energy ( Question )

  1. Jan 2, 2008 #1
    1. The problem statement, all variables and given/known data

    A copper cube mass of 110g is heated to a temperature of 100 Celcius degrees and then rapidly transferred to a well insulated aluminium can of mass 80g containing 200g of water at 10 C degrees . If the final temperature of the cube and water ( after stirring ) is 14 C .

    ( c of water and al are 4.2 x 10^3 J/Kg/K and 9.1 x 10^2 J/Kg/K

    2. Relevant equations

    Calculate the specific heat capacity of the copper . Assuming heat loss to the surrounding is negligible .

    3. The attempt at a solution

    Heat supplied = heat loss . However i`m struggling with the change in temperature .
  2. jcsd
  3. Jan 3, 2008 #2


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    The change in temperature of the copper is -86C and the change in the water is +4C?? Is that what you are asking??
  4. Jan 3, 2008 #3
    No i mean about the change of a can .
    It should be heat supplied = heat gained isn't it ?
    Q of Copper cube = Q of can + Q of Water ?

    If can and water are only one object then why would they give us C of aluminum ?
  5. Jan 3, 2008 #4


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    I think you can take the temperature change of the can to be the same as the water it contains.
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