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Thermal equilibrium

  1. May 27, 2016 #1

    TT0

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    1. The problem statement, all variables and given/known data
    A hot (800 K) iron nail of mass 150 g is placed into a 1.0 kg of water at 25°C. What is the common temperature of the 2 objects once they have reached thermal equilibrium? Assume no change of state of the water.

    Heat capacity of iron nail is 450 J/kg/K
    Heat capacity of water is 4138 J/kg/K

    2. Relevant equations
    Q=mc∆T

    3. The attempt at a solution
    Q lost in nail=Q gained in water

    let T = final temperature

    0.15*450*(800-T)=1*4138*(T+25+273)
    T=-280.38 K

    I don't know why it is negative. Can someone explain what I did wrong?
     
  2. jcsd
  3. May 27, 2016 #2
    (T+25+273) should be a difference between the final temperature and initial temp.
     
  4. May 27, 2016 #3

    TT0

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    I see thanks!
     
  5. May 27, 2016 #4

    TT0

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    Is the answer 33.06 C?
     
  6. May 28, 2016 #5
    Seems reasonable
     
  7. May 28, 2016 #6

    TT0

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    Thanks again!
     
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