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Thermal expansion and a pendulum clock

  1. Sep 7, 2004 #1
    I need a little help. The problem is as follows:

    A pendulum clock with a pendulum made of brass is designed to keep accurate time at 18 °C. If the clock operates at 0.0°C, what is the magnitude of its error, in seconds per hour (use a minus sign to indicate slowing down)? The linear expansion coefficient of brass is 19 x 10-6 /C°.

    I tried multiplying the change in temperature by the coefficient of brass, but that does not come out right. I also tried multiplying that answer by 3600 to get the seconds but that was not right either. What else is there to do? :confused:
  2. jcsd
  3. Sep 7, 2004 #2


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    Did you use the fact that the period of the pendulum is proportional to [itex]\sqrt L[/itex]?
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