The equatorial radius of the earth is about 6370km. Consider a 40,000 km long steel pipe that forms a giant ring that fits snugly around the equator of the earth. Suppose the temp. of the pipe is increases 1 degree C. The pipe gets longer. it is also no longer snug. How high does the pipe stand off the ground? Assume that D L = L o x 1/100,000 x D T . I came up with .07 km. The radius of the pipe is actually 6369.42 km. When the temperature of the pipe is increased 1 degree Celsius it will expand .4 km making the pipe 40000.4 km. 40000.4 / 3.14 = 12738.98. 12738.98 / 2 = 6369.49 (radius) 6369.49- 6369.42 is .07km. Am I right?