a)A steel I-beam is 30m long, and its cross-sectional area is .001 square meters. If its temperature is increased by 80C what is its change in length?
Ysteel = 20x10^10 N/m^2
(Alpha)steel = 1.2x10^-5/C
b) How much force should be applied to keep it from expanding?
(Delta)L = (Alpha)(Delta)T * L
The Attempt at a Solution
We've solved (we think) (Delta)L to be .0288.
[(Delta)L = (1.2*10^-5)(80)(30) = .0288
Our question is how to approach b part. We're unable to find much of anything in our notes,text, etc... related to these kinds of forces of expansion!
We're somewhat confident about our solution to a part, though any observations on our mistakes would be appreciated!