- #1

- 187

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what i was thinking of doing here is setting up two equations for the lengths as functions of temperature and equating them. i dont know what the equations are though that i am supposed to use here. thanks for the help.

- Thread starter thenewbosco
- Start date

- #1

- 187

- 0

what i was thinking of doing here is setting up two equations for the lengths as functions of temperature and equating them. i dont know what the equations are though that i am supposed to use here. thanks for the help.

- #2

- 10

- 0

try putting 0.01cm on one side, and that has to equal the difference (radius of aluminum) - (radius of brass ring). this is found by using the thermal expansion coefficient and the measurments at 20 C. 2.4 x 10^-5 per degree C for alum, 2.0 x 10^-5 per C for brass. this means that (10.00*2.0*10^-5*(20-T)) is the expansion or contraction for the brass ring. you want this value minus the value of the alum to be equal to 0.01.

set this equation up, solve for T, make sure you got the organization of the minus signs and differences correct. if your T is greater than 20, its not making sense. you would have the solution for when the rod would be .01 bigger than the ring. if you go over this Temperature you solve for, the rod always expands more. so make sure you get that right.

Im not sure if thats right, but it might help you.

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