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coffeem
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Homework Statement
3 Moles of a monotomatic ideal gas undergo an isothermal (T=50 Degrees Clecius) reversible expansion from a volume of 3m^3 and a pressure P1 to a volume V2 and a pressure P2. The gas does 9.7kJ of work in the expansion. Find:
a) the pressure P1
b) The volume V2
c) The pressure P2
d) The amound of heat that flows during the expansion
The attempt at a solution
My attempt is as follows:
n = 3
T = 323K
V1 = 3m^3
a) P1V1 = nRT
rearanging:
P1 = 2680Pa
b) I am slightly more stuck on:
for an isothermal expansion: dW = -PdV
by subbing into the ideal gas eq" of state:
W = nRTln(V1/V2)
Now since change in T = 0, therefore the chance in E = 0.
and first law of thermodynamics: E = Q +W
therefore Q = -W
so Can i just rearrange with this to find V2 from the expression for work? thanks
3 Moles of a monotomatic ideal gas undergo an isothermal (T=50 Degrees Clecius) reversible expansion from a volume of 3m^3 and a pressure P1 to a volume V2 and a pressure P2. The gas does 9.7kJ of work in the expansion. Find:
a) the pressure P1
b) The volume V2
c) The pressure P2
d) The amound of heat that flows during the expansion
The attempt at a solution
My attempt is as follows:
n = 3
T = 323K
V1 = 3m^3
a) P1V1 = nRT
rearanging:
P1 = 2680Pa
b) I am slightly more stuck on:
for an isothermal expansion: dW = -PdV
by subbing into the ideal gas eq" of state:
W = nRTln(V1/V2)
Now since change in T = 0, therefore the chance in E = 0.
and first law of thermodynamics: E = Q +W
therefore Q = -W
so Can i just rearrange with this to find V2 from the expression for work? thanks