1. The problem statement, all variables and given/known data Dry steam is used to make a cup of coffee by bubbling it through water. If the steam is at 100°C, what mass of steam must be used to heat 200 g of water from 25°C to 95°C? 2. Relevant equations Not quite sure but I think: Q= mCΔT Qcold=-Qhot 3. The attempt at a solution Ok so I started out by trying to use Qcold=-Qhot, and this was what I did: Hot: m=?? C=2020 (this is what the textbook said the specific heat of steam was) Ti=100°C Tf= 95°C (because I assumed that they would end up the same temp because of equilibrium) Cold: m=0.2kg C=4200 (textbook said this was specific heatr for water) Ti=25°C Tf=95°C So then I subbed in values to come up with: 4200x0.2(95-25)=-(2020m(95-100)) 58800=10100m m=5.82kg this is a ridiculous number and the text book says that the answer is 26g. Please help me understand this.