# Thermal Physics - STEAM

## Homework Statement

A perfectly insulated calorimeter cup(it niether gains nor loses energy) contains 300 grams of water at 10.0 degrees Celsius. If 15.0 grams of steam at 150 degrees Celsius are added to the water, what final equilibrium temp is reached?

## Homework Equations

Qlost = Qgain
(msteam)(csteam)($$\Delta$$Tsteam)+(msteam)(Lv)=(Mwater)(Cwater)($$\Delta$$Twater)

## The Attempt at a Solution

(15g)(.480cal/gm$$\circ$$C)(Tf-150$$\circ$$C)+(15g)(540cal/gm)=(300g)(1.00cal/gm$$\circ$$C)(Tf-10$$\circ$$C)

(7.2)(Tf-150$$\circ$$C)+(8100)=(300)(Tf-10$$\circ$$C)

(7.2Tf)-(1080)+(8100)=(300Tf)-(3000)

(7.2Tf)+(7020)=(300Tf)-(3000)

(10020)=(292.8Tf)

(Tf)=(34$$\circ$$C)