1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Thermal Physics - STEAM

  1. May 5, 2009 #1
    1. The problem statement, all variables and given/known data
    A perfectly insulated calorimeter cup(it niether gains nor loses energy) contains 300 grams of water at 10.0 degrees Celsius. If 15.0 grams of steam at 150 degrees Celsius are added to the water, what final equilibrium temp is reached?

    2. Relevant equations
    Qlost = Qgain
    (msteam)(csteam)([tex]\Delta[/tex]Tsteam)+(msteam)(Lv)=(Mwater)(Cwater)([tex]\Delta[/tex]Twater)


    3. The attempt at a solution

    (15g)(.480cal/gm[tex]\circ[/tex]C)(Tf-150[tex]\circ[/tex]C)+(15g)(540cal/gm)=(300g)(1.00cal/gm[tex]\circ[/tex]C)(Tf-10[tex]\circ[/tex]C)

    (7.2)(Tf-150[tex]\circ[/tex]C)+(8100)=(300)(Tf-10[tex]\circ[/tex]C)

    (7.2Tf)-(1080)+(8100)=(300Tf)-(3000)

    (7.2Tf)+(7020)=(300Tf)-(3000)

    (10020)=(292.8Tf)

    (Tf)=(34[tex]\circ[/tex]C)
     
  2. jcsd
  3. May 5, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper


    (15g)(.480cal/gmLaTeX Code: \\circ C)(Tf-150LaTeX Code: \\circ C)+(15g)(540cal/gm)=(300g)(1.00cal/gmLaTeX Code: \\circ C)(Tf-10LaTeX Code: \\circ C)

    In left hand side you have substituted 0.480 csl/g/oC for th specific heat of the water and in right hand side 1.00 cal/g/oC for the same thing. How is that?
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Thermal Physics - STEAM
  1. Thermal Copper Physics (Replies: 1)

  2. Thermal Physics (Replies: 1)

  3. Thermal Physics (Replies: 1)

  4. Thermal Physics (Replies: 8)

Loading...