1. The problem statement, all variables and given/known data 0.02 kg of ice and 0.10 kg of water at 0 degrees Celsius are in a container. steam at 100 degrees Celsius is passed in until all the ice is just melted. How much water is now in the container? Specific latent heat of steam = 2.3 * 10^6 J/kg Specific latent heat of ice = 3.4 * 10^5 J/kg Specific heat capacity of water = 4.2 * 10^3 J/kg/K 2. Relevant equations latent heat Q = mL Specific Heat Capacity Q = mCT Where Q = Heat required m = mass of substance C = Specific heat Capacity T = change in Temperature 3. The attempt at a solution Using latent heat equation, the heat required for a phase change from ice to water Q = 0.02 (3.4 x 10^5) = 6800 J Using Specific heat capacity equation, the heat require for water Q = 0.10(4.2 x 10^3)100 = 42,000 J Total heat required 6800 + 42000 = 48,800 J plugging in 48,800 into latent heat equation for steam 48,800 = m (2.3 x 10^6) m = 0.0212 kg will this answer be the mass of the water in the container? or am i missing steps or is completely wrong with my workings???