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Thermal Processes

  1. Nov 30, 2005 #1
    This question is considered one of the hardest in this chapter regarding thermodynamics. I spent countless time trying to figure it out but i was never close to the answer. The question is:

    Water is heated in an open pan where the air pressure is 1atm. WAter remains a liquid but expanded by a small amount when it was heated. FIND THE RATIO OF WORK DONE BY WATER TO THE HEAD ABSOBED BY THE WATER.

    So that means:

    W / Q

    where W = P(Vf - Vi)
    but what's Q? I tried Q = cm delta T but i was wrong. if anyone can help me i'd appreciate it thanks.
  2. jcsd
  3. Dec 1, 2005 #2

    Meir Achuz

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    Q=cm delta T seems right. Did you convert calories to Joules?
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