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Thermal processes

  • Thread starter yossup
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  • #1
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Homework Statement



A 1.20mol sample of an ideal monatomic gas, originally at a pressure of 1.00 atm, undergoes a three-step process: (1) it is expanded adiabatically from T1 = 592k to T2 = 390k ; (2) it is compressed at constant pressure until its temperature reaches T3; (3) it then returns to its original pressure and temperature by a constant-volume process.

Determine T3.

Homework Equations



E= 3/2 nRT

The Attempt at a Solution



So from T1 to T2, change in energy is -3022.97J. E at T1 8859.398J and E at T2 is 5836.4284J. From T2 to T3, it's isobaric. i found initial volume (at T1) to be .0583m^3. how do i go from here?
 

Answers and Replies

  • #2
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bbbbump :(
 
  • #3
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So what is your question exactly? You might want to work backwards from T1 to help you determine T3 if thats what your after.
 
  • #4
Ygggdrasil
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What does step 3 tell you about the volume at the end of step (2)?
 
  • #5
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the volume at the end of step (2) is the same volume as the volume at T1.
 
  • #6
Ygggdrasil
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So now you just need to find the pressure at the end of step (2), and you'll have T_3.
 

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