# Thermal processes

## Homework Statement

A 1.20mol sample of an ideal monatomic gas, originally at a pressure of 1.00 atm, undergoes a three-step process: (1) it is expanded adiabatically from T1 = 592k to T2 = 390k ; (2) it is compressed at constant pressure until its temperature reaches T3; (3) it then returns to its original pressure and temperature by a constant-volume process.

Determine T3.

E= 3/2 nRT

## The Attempt at a Solution

So from T1 to T2, change in energy is -3022.97J. E at T1 8859.398J and E at T2 is 5836.4284J. From T2 to T3, it's isobaric. i found initial volume (at T1) to be .0583m^3. how do i go from here?

## Answers and Replies

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bbbbump :(

So what is your question exactly? You might want to work backwards from T1 to help you determine T3 if thats what your after.

Ygggdrasil
Gold Member
2019 Award
What does step 3 tell you about the volume at the end of step (2)?

the volume at the end of step (2) is the same volume as the volume at T1.

Ygggdrasil