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Homework Help: Thermo and Projectile motion

  1. Feb 23, 2010 #1
    1. The problem statement, all variables and given/known data
    A person of mass 70.0 kg is sitting in the bathtub. The bathtub is 190.0 cm by 80.0 cm before the person got in, the water was 10.0 cm deep. The water is at a temperature of 37.0 C. Suppose that the water were to cool down spontaneously to form ice at 0.0 C, and that all the energy released was used to launch the hapless bather vertically into the air.


    2. Relevant equations




    3. The attempt at a solution

    Density of Water = 1000 kg/m^3

    Volume of water
    1.9 * 0.8 * 0.1 = 0.152 m^3

    Mass of water
    0.152 m^3 * 1000 kg/m^3 = 152 kg

    Energy of cooling water = mcT
    152 * 4190 * (0-37) = 2.356456 x 10^7

    Energy of freezing water = mL
    -152 * 3.34*10^5 =-5.092 x 10^7

    Sum of Energy
    -7.433256 x 10^7


    nvm got it..
    h=KE/mg
     
  2. jcsd
  3. Feb 23, 2010 #2

    ideasrule

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    Homework Helper

    Have you learned about gravitational potential energy yet?
     
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