- #1

- 211

- 2

1. does 'in direct proportion to it volume' mean Pf = Pi * Vf/Vi or should there be a proportionality constant a?

2. I calculated the work done on the gas by using P(v) = a*V and using W = -[inte] aVdV = -a/2 * (Vf^2 - Vi^2) Comments?

3. I am having more trouble getting change in internal energy dU.

I tried PV = NkT so PfVf - PiVi = Nk( Tf - Ti) and

dU = 3Nk (Tf - Ti)/2 so that

dU = 3/2 * (PfVf-PiVi) = 3/2 * (4*4*aVi - Vi)

Is this even close?

4. If I can get 2 and 3 I can calculate Q myself!