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## Homework Statement

What will be the final temperature of the water in an insulated container as the result of passing 5.00 of steam at 100.0 into 100.0 of water at 27.0?

## Homework Equations

q=mct

q=nH

## The Attempt at a Solution

I am completely lost as to how to solve for final temperature, I attempted it, but it didn't work, this is what I did.

n=5.00g/(18.02g/mol)=0.277 mol

q=(0.277 mol)*(40.6KJ/mol)=11.27KJ

11.27KJ=mct

11.27KJ=(100g)*(4.18)*(Tf-27)

(11.27/418)=Tf-27

Tf=(0.02696)+27=27.0

can someone please help, I am so lost :( I don't understand what it is that i'm doing wrong