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Calculating Molar Heat of Reaction for Ca + HCl
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[QUOTE="haydn, post: 2087715, member: 149925"] [h2]Homework Statement [/h2] When 0.612 g of Ca metal is added to 200.0 mL of 0.500 M HCl(aq), a temperature increase of 100C is observed. Assume the solution's final volume is 200.0 mL, the density is 1.00 g/mL, and the heat capacity is 4.184 J/gC. (Note: Pay attention to significant figures. Do not round until the final answer.) The molar heat of reaction, H rxn, for the reaction of Ca[SUB](s)[/SUB] + 2H[SUP]+[/SUP][SUB](aq)[/SUB] => Ca[SUP]2+[/SUP][SUB](aq)[/SUB] + H[SUB]2 (g)[/SUB] [h2]Homework Equations[/h2] Q=mc[tex]\Delta[/tex]T [h2]The Attempt at a Solution[/h2] All I know is that mc[tex]\Delta[/tex]T is used... Our professor hasn't taught us how to do this yet so that's about all I know. Would I divide Q by the number of moles formed? [/QUOTE]
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Calculating Molar Heat of Reaction for Ca + HCl
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