Since heat flow (Q) is zero, use:vaishakh said:Can anyone here help me to derive that during an adiabatic expansion, PV^gamma?is a constant, as well as other expressions similar to the above?
This follows from the adiabatic condition. One can express the work as:I have found the following equation using definite integration and the basic formulae, nRdT/gamma - 1 = work done.