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## Homework Statement

All i want to know is how do i find the temperature of my heat and cold reservoir, given that they have a 90 degree celsius/kelvin differential and a 28% efficency.

## Homework Equations

Efficency= Work out/ Work in = 1- Q out/Q in

## The Attempt at a Solution

I been thinking all night and couldn't sleep well over this, i know how to get efficency but it seems a tricky question, how ever i was thinking of just calculating the heat and work for many diferent temperatures with 90 degrees differential and then see what happens?

Anyone has a better idea? I feel very reluctant of making so many calculations...