1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Thermodynamics: Derive Modifications for TdS equations for Wire under Constant Force

  1. Nov 10, 2012 #1
    1. The problem statement, all variables and given/known data

    I have been stuck on the following question for a while now, particularly part B and C, and I'd like some help with it please. I've completed part A already. The Question:

    (A) Combine the following TdS equations:

    [itex]TdS = C_{v} dT + T\left(\frac{\partial P}{\partial T}\right)_{v}dV[/itex]
    [itex]TdS = C_{P} dT - T\left(\frac{\partial V}{\partial T}\right)_{p}dP[/itex]

    to derive a relationship for [itex]C_{p} - C_{v}[/itex] as a function of volume, pressure and temperature (V, P and T, respectively) using the cyclic rule.

    (B) Derive modifications to the two TdS equations, mention in part A, for application to a stretched wire under constant force (for example, supported by a weight). The force on the wire can be considered solely as a function of length, L, and temperature, T. Derive the modified equations in terms of the coefficient of linear expansion with temperature and Young's modulus.

    (C) Derive a relationship for [itex]C_{F} - C_{L}[/itex] for a stretched wire under constant force (for example, supported by a weight). The force on the wire, F, can be considered solely as a function of the length, L, and temperature, T. Derive this relationship in terms of the coefficient of linear expansion, Young's modulus, volume and temperature. You may use the relationship that you derived in part (A).


    2. Relevant equations
    (1) Volume expansivity: [itex]\beta = \frac{1}{V}\left(\frac{\partial V}{\partial T}\right)_{p}[/itex]
    (2) Bulk modulus: [itex]K = - V\left(\frac{\partial P}{\partial V}\right)_{T}[/itex]
    (3) Young's modulus: [itex]Y = \frac{L}{A}\left(\frac{\partial F}{\partial L}\right)_{T}[/itex]
    (4) Coefficient of Linear Expansion: [itex]\alpha = \frac{1}{L}\left(\frac{\partial L}{\partial T}\right)_{F}[/itex]

    3. The attempt at a solution

    I've completed part A of the question and got the following expression using the cyclic rule:

    [itex]C_{p} - C_{v} = - T\left(\frac{\partial V}{\partial T}\right)^{2}_{P}\left(\frac{\partial P}{\partial V}\right)_{T}[/itex]

    I know that the above expression for [itex]C_{p} - C_{v}[/itex] can be written as;

    [itex]C_{p} - C_{v} = T\beta^{2}KV[/itex]

    where β and K are the volume expansivity and the bulk modulus, respectively and [itex]\beta\approx 3\alpha[/itex].

    However, I really don't know where to start with part B.

    Could someone please help me with part B and C of this question? If I knew how to do part B I think I'd be able to derive a relation for part C.

    I would really appreciate any help. Thank You!
     
  2. jcsd
  3. Nov 11, 2012 #2
    Re: Thermodynamics: Derive Modifications for TdS equations for Wire under Constant Fo

    Anyone? Any help greatly appreciated.
     
  4. Nov 12, 2012 #3
    Re: Thermodynamics: Derive Modifications for TdS equations for Wire under Constant Fo

    Please, anyone....
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Thermodynamics: Derive Modifications for TdS equations for Wire under Constant Force
  1. Force on a wire (Replies: 5)

Loading...