- #1

zulfiqar6

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## Homework Statement

Steam at 200psia and 600 *F [state 1] Enters a turbine through a 3-inch-diameter pipe with a velocity of 10(ft)/(s). The exhaust from the turbine is carried through a 10-inch-diameter pipe and is at 5psia and 200 *F [state 2]. What is the power output of the turbine?

H1 = 1,322.6(Btu)/lbm

H2 = 1148.6(Btu)/lbm

V1 = 3.058ft^3 / lbm

V2 = 78.14ft^3 / lbm

## Homework Equations

dH = (u^2 / 2*gc) + Q + W

## The Attempt at a Solution

dH = -174Btu/lbm

174Btu/lbm = du/2gc + Q + W

mass flowrate = (A1*u1) / V1 == 0.1605 lbm/s

final velocity u2 = (m * V2) / A2 = 23.0 ft/s

du = 13ft/s

What do I do now? How do I calculate Q and W?

there are tables at the back of the book with properties of steam for various temperatures and pressures...some of the example problems I looked at make use of that, but I'm not quite sure how that helps here.