1. The problem statement, all variables and given/known data Find (a) the energy absorbed as heat and (b) the change in entropy of a 2.00 kg block of copper whose temperature is increased reversibly from 25°C to 100°C. The specific heat of copper is 386 J/kg K . 2. Relevant equations dS=dQ/T dS=nRln(final volume/initial volume) **for an ideal gas** 3. The attempt at a solution\ Well I got the first part. The energy is just dQ=cmdT which is (386)(2)(75K)= 57900J however, when i got to the second part, I didn't know what to do since the copper isn't an ideal gas, and it has a non-constant temperature so I can't use the first equation. Any help would be appreciated!!!