1. The problem statement, all variables and given/known data A 2.3kg aluminum pan at 135° is plunged into 3.0kg of water at 15°. The specific heat of aluminum is 900 J/(kg K). Part A Find the final Celsius temperature of the aluminum and water. T_f = °Celsius Part B Find the entropy change of the aluminum pan. ΔS_Al = J/K Part C Find the entropy change of the water. ΔS_H20 = J/K Part D Find the entropy change in the system of particles consisting of all the particles in the aluminum plus all the particles in the water. ΔS = J/K 2. Relevant equations Q=mCΔT ΔS=Q/T 3. The attempt at a solution So my first couple attempts was that we use the equation Q=mC(T_f-T_i) other related equations i know is DeltaS=Q/T but, how can i find the temperature final of both Water and aluminum. I tried setting it up like this m_water*C_water(T_f-T-i) + m_aluminum*C_aluminum(T_f-T_i) = Q_total but i don't know how to get anything done from there. Please help me with the first part and i should be able to most of it done on my own.