Thermodynamics help

1. Jan 25, 2007

wub1098

Consider a U-tube whose arms are open to the atmosphere. Now water is poured into the U-tube from one arm, and light oil (p=790 kg/m^3) from the other. One arm contains 70 cm high water, while the other arm contains both fluids with an oil-to-water height ratio fo 4. Determine the height of each fluid in that arm.

any help an explanation would be greatly appreciated

2. Feb 22, 2007

eaboujaoudeh

Ok simple, we know that the pressure exerted by a fluid is explained by the following relation: P= rho * g * height of water. g is the gravity. now on the water side we have P = Rho of water*g*H on the other side we have
P= Rho water*g*H1 + Rho Oil*g*4H1 (since height of oil is 4 times that of water). since we are in equilibrium then the pressures will be equal. P1=P2. g cancels from both equations, and the rest are known values leaving us with H1 to figure out.Easy ?

3. Feb 22, 2007

eaboujaoudeh

btw this is not even close to thermodynamics !!

4. Feb 23, 2007

FredGarvin

Please re read the forum's guidlines for the posting of homeowork questions as well as providing answers.