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Thermodynamics Help

  1. Mar 28, 2007 #1
    1. The problem statement, all variables and given/known data

    A steel can, open at one end, closed at the other, 8inches high, with a diameter of 3inches, is submerged in water vertically with the open end facing down. What is the height of the air inside the can when:
    a) the cans closed end is in level with water surface?
    b) the can is 7inches below water surface?

    Temperature is constant.


    2. Relevant equations

    pressure1*volume1 = presure2*volume2

    3. The attempt at a solution


    -----

    any help would be helpful. thanx.
     
  2. jcsd
  3. Mar 28, 2007 #2

    FredGarvin

    User Avatar
    Science Advisor

    What can you say about the air in the can as you lower the can in the water? As you lower the can, the water pressure increases. Since the air trapped in the can has no where to go, the air pressure will equalize with the water pressure (which increases with depth), but the volume will have to change because the air compresses.

    You have the equation you need. You simply need to get the physical situation straight.
     
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