1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Thermodynamics of a perfect liquid, help please

  1. Jan 26, 2010 #1
    1. The problem statement, all variables and given/known data

    Water, assumed to be a perfect liquid, has a density of 1000 kg/m3 and a specific heat of 4184 J/kgK. The water undergoes an adiabatic, frictionless process in which its pressure is raised from 200 kPa to 1500 kPa. Find:
    1. change in temperature
    2. change in specific internal energy
    3. change in specific enthalpy
    4. temperature change required for isobaric process to change the enthalpy that same amount as in part 3

    2. Relevant equations

    ds = c ln(P2/P1)
    Tds = de
    Tds = dh

    3. The attempt at a solution

    I have done the following, is this correct logic?

    1. ds = c ln(P2/P1) = 4184 ln(1500/200) = 8430
    Tds=cdT => dT = Tds/c = (298*8430)/4184 = 600K
    so change in temp dT = 600K

    2. Tds = de
    de = 298 * 8430 = 2512 kJ/kg

    3. Tds = dh
    dh = 298 * 8430 = 2512 kJ/kg

    4. Im not quite sure how to do this part.

    Any help or suggestions are appreciated.
     
  2. jcsd
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Can you offer guidance or do you also need help?
Draft saved Draft deleted



Similar Discussions: Thermodynamics of a perfect liquid, help please
Loading...