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wintermute++
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Homework Statement
A sample of gas is contained in a cylinder-and-piston arrangement. It undergoes the change in state shown in the drawing. (The drawing shows the first state of the piston as and uncompressed gas, then the second state is compressed, possibly a liquid, with the piston having moved downward and decreasing the volume) a. Assume first that the cylinder and piston are perfect thermal insulators that do not allow heat to be transferred. What is the value of q for the state change? What is the sign of w for the state change? What can be said about the change in Internal Energy for the state change? b. Now assume that the cylinder and piston are made up of a thermal conductor such as a metal. During the state change the cylinder gets warmer to the touch. What is the sign of q for the state change in this case? Describe the difference in the state of the system at the end of the process in the two cases. What can you say about the relative values of changes in Internal Energy?
Homework Equations
w = -PV
E = q + w
The Attempt at a Solution
a. Work is done on the system and is positive. This is the part that I'm stumbling over. If the cylinder is a perfect thermal insulator, then no transfer of heat can occur with the surroundings and since heat is the flow of energy from a hotter object to a cooler object, would q = 0 then or would it still be q < 0?
b. The change in state is exothermic with q being negative. If my above assumption is true and q = 0, then the relative changes in internal energy would be: the perfect thermal insulator has an overall increase in internal energy and the thermal conducting cylinder would have either a very small increase in internal energy or a decrease in internal energy.
Bah, thermodynamics are the only part of chemistry I struggle to get a firm grasp on. Please help!