- #1
physicsnnewbie
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You take a jug of water from the refrigerator, and pour 240mL of it into a glass. The temperature of the beverage is 10.5ºC. You then add one 45g ice cube at 0ºC.
Determine the final temperature and the amount of ice remaining if any.
I've tried to work it out below, but my I must've made an error because the temperature has to be between 0 and 10.5. Where have I gone wrong?
4.184*240(x-10.5) = -[45*333+4.184*45(x-0)]
1004.16x - 10543.68 = -[29970+376.56x]
1004.16x - 10543.68 = -29970-376.56x
1,380.72x - 10543.68 = -29970
1,380.72x = -19,426.32
x = -19,426.32/1,380.72
x = -14.06970276
thanks
Determine the final temperature and the amount of ice remaining if any.
I've tried to work it out below, but my I must've made an error because the temperature has to be between 0 and 10.5. Where have I gone wrong?
4.184*240(x-10.5) = -[45*333+4.184*45(x-0)]
1004.16x - 10543.68 = -[29970+376.56x]
1004.16x - 10543.68 = -29970-376.56x
1,380.72x - 10543.68 = -29970
1,380.72x = -19,426.32
x = -19,426.32/1,380.72
x = -14.06970276
thanks