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Thermodynamics problem

  1. Feb 14, 2016 #1
    If for two reversible processes we have the same internal energy change, if work done is maximum for one, is heat transfer minimum and vice versa?
    The logic that I use is that since dU=dQ+dW, for constant dU if dW is more for one, heat transfer dQ is less and vice versa just to keep the sum constant.
    Is my logic correct or wrong?
     
  2. jcsd
  3. Feb 14, 2016 #2
    Your logic is essentially correct. Using the First Law for a process between state 1 and state 2,
    U2-U1 = Q-W,

    which leads to the same conclusion.​
     
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