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Thermodynamics question

  1. Oct 18, 2006 #1
    hey guys got this question that i have been stuck on for a while.

    air is expanded from 1M Pa at 327 degrees celcius to 200kPa in a closed piston cylinder device. for the process PV^1.2 = constant. calculate the work done during this process

    any help will be welcomed

  2. jcsd
  3. Oct 18, 2006 #2
    temperature constant? work done= -pV ?
  4. Oct 18, 2006 #3
    if [P(V^1.2) = constant] this is an adibatic process which means that there is no heat added or taken away.
  5. Oct 19, 2006 #4
    I have not encountered something like V^1.2 before. Is that right? If so can someone enlighten me about it?
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