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Thermodynamics Homework: Solving the Mystery of Internal Energy Change
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[QUOTE="Chestermiller, post: 4878222, member: 345636"] From the first law, for an adiabatic process, [SIZE=4]##\Delta U=-W##, where W is the work done by the gas on the surroundings. In this situation, W is negative (the surroundings do work on the gas), so that ##\Delta U## is positive. The temperature of the gas actually rises, even though no heat was transferred to the gas. This is the same thing that happens when you compress air with a bicycle pump. Chet[/SIZE] [/QUOTE]
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Thermodynamics Homework: Solving the Mystery of Internal Energy Change
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