This is an open-whatever take-home homework quiz. Could someone check my work? Thanks.
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That's my site. Try it again. I just made an html page. Thanks.Sorry, but your link is giving a 403 message. The site may not be permitting direct linking to .jpgs (tried both clicking and copy-and-pasting...).
You may need to link to a specific page at the site or use some other free-host...
It's a jpeg. Shoot me an email address, and I'll just send it to you, or something. I have AIM, too.All right, still isn't working for me. I'm on a Mac, so I don't "right-click", but I can download and save to the desktop. It downloaded 8K of something, but I can't read it. Are you sure the image is formatted as a .jpg ? (Just giving something a .jpg file extension doesn't make it one...).
If you have set it up correctly, I may have to bow out, as my antique home machine may not be dealing with this... (If so, my apologies.)
If you click on my name on my posts, you will get taken to my "profile page". Try sending the image as an attachment on a private message AND go to the Contact Info near the bottom of the page and click on the link to send me an e-mail. We'll see (if only for future reference) if that works...Shoot me an email address, and I'll just send it to you, or something. I have AIM, too.
I didn't see the option to attach an image in the PM.If you click on my name on my posts, you will get taken to my "profile page". Try sending the image as an attachment on a private message AND go to the Contact Info near the bottom of the page and click on the link to send me an e-mail. We'll see (if only for future reference) if that works...
That's weird. I see the attachment.The forum didn't like your attachment...
And sorry about the PM: attachments work for some forum types, but not this one, I guess.
Go to my profile and try the e-mail link (I'm curious to see what works around here...).
I guess that's what puzzles me. The delta_H is given in kJ/mole , not kJ for the entire reaction. Perhaps I should ask what it is that the enthalpy change is being given per mole of.From the equation, the change in enthalpy of 143.5 kJ/mole is for two moles of Na2O2. That's why I multiplied (1.92/2) times the given change in enthalpy value to reflect that. Four moles would give twice the change in enthalpy value and so on.
I don't know offhand how many helpers read that section of the Forum. It may be that you didn't get responses because of the problem with the link to your quiz image. You're welcome to use my link in your post over there; maybe you'll get a bite this time...Heh. I actually did post this in Other Sciences first, but someone has still yet to respond. Thanks for your help. I'll probably be posting these as we get them.