# Thermodynamics, Specific Heat

1. Jul 28, 2011

### mateomy

I think I might have a hard time adequately explaining my issue, but here we go…

So everyone knows the Q=mc(delta)T equation, I have this problem that I am working on and it was driving me CRAZY! So I checked out the solutions manual after some time.

Basically the stated a mass of copper was sliding across a slab of ice (Ice, air, and copper were all at 0 degrees Celsius), it said the block eventually comes to rest due to friction. It only gave the mass of the copper (1.60kgs) and the speed (2.50 m/s) and wanted to know the mass of the ice that melted due to the sliding copper. It mentioned looking at the internal energy of the system; both ice and copper, and determining for each what the changes were.

Here's the solution to the first part of the problem…

The thing that Im not sure about is substituting the Kinetic value as the Q value as shown in the latent heat calculation. Can you do that? Can you just substitute any energy as the "Q" variable?

Does that make sense? Im on about 15 hours of studying and I think I might be brain-dead.

Thanks.

2. Jul 28, 2011

### Isak BM

You can, but only under certain assumptions.

It would seem necessary to assume the following in order to solve the problem as they have done:

- The mass of the ice slab is sufficiently large, such that not all of the ice melts.

- Sublimation (ice -> vapor) does not occur.

- All of the kinetic energy is transformed into heat that is directly or over time indirectly "given" to the ice to cause it to melt (ice -> liquid).

Almost always in physics you have to come up with the right assumptions, and you need to specify why they are good assumptions. It's hard to think of any problem in physics where you don't assume something. This is often the trickiest part of doing physics. Realizing what assumptions you need to make, and why you make them. In this example (your problem), it is wise and perhaps even adequate to assume that all of the kinetic energy is transferred to the surrounding ice and results in the melting of said ice. Although it would be possible to look further into the problem at hand, the results shouldn't deviate that much.

The above assumptions are somewhat good enough to get a rough idea of what happens, and they are valid assumptions as the problem doesn't state specifically the pressure of the surrounding air and other important factors (that would govern the process of sublimation).

I hope this helped! :)

3. Jul 28, 2011

### mateomy

Definitely helped, thank you.