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Thev and Norton Equiv

  1. Oct 26, 2008 #1
    1. The problem statement, all variables and given/known data


    2. Relevant equations

    Why did the 10 ohm resistor turn into a 5 ohm resistor when we make it an open circuit.

    This is not a homework question, it was an example problem given to us to help prepare for our midterm.

    3. The attempt at a solution

    Normally, when I try and find my Th and Norton equivalents, there is a voltage. Deactivating the sources doesn't change any of the values (in the problems i've done).

    When Solving something like I would find Req and then apply current division. Afterwards I can apply ohm's law to find Vth.

    However, it doesn't work out to the answer i am supposed to get because of how the resistor changed.

    Can someone explain to me why this is happening? Or is it simply a typo?
    Last edited: Oct 26, 2008
  2. jcsd
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