Thevenin equivalent circuit

  • Engineering
  • Thread starter john88
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  • #1
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Homework Statement





Homework Equations





The Attempt at a Solution



I trying to figure out a thevenin equivalent circuit

I want to calculate the current I so I cant get the resistance for the thevenin equivalent.

Im not 100% sure how to calculate I, can I use KCL on the node under the number -8.7V?

http://img98.imageshack.us/my.php?image=curfc7.jpg
 
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Answers and Replies

  • #2
Defennder
Homework Helper
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That sure is a complex circuit. To find Rth, kill all the current and voltage sources and then measure the equivalent resistance between A&B.

KCL is valid everywhere. Is that -6.7 and -8.7 node voltages given by the question? If so, then you can easily find Isc. Also note that the 1mA source is connected in parallel with a short-circuited wire.
 
  • #3
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so if short circuit the system. Can I setup KCL on node A and then solve for I,
I = I(source) + I(R10).

But it seems odd to do so.
 
  • #4
Defennder
Homework Helper
2,591
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You got the equation wrong. It's IR10 = Isource + I. Be careful of the direction designated for Isc.
 
  • #5
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ok, got everything together now, ty for the help!
 

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