Thevenin equivalent circuit

1. Sep 4, 2008

john88

1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

I trying to figure out a thevenin equivalent circuit

I want to calculate the current I so I cant get the resistance for the thevenin equivalent.

Im not 100% sure how to calculate I, can I use KCL on the node under the number -8.7V?

http://img98.imageshack.us/my.php?image=curfc7.jpg

Last edited: Sep 4, 2008
2. Sep 4, 2008

Defennder

Re: thevenin

That sure is a complex circuit. To find Rth, kill all the current and voltage sources and then measure the equivalent resistance between A&B.

KCL is valid everywhere. Is that -6.7 and -8.7 node voltages given by the question? If so, then you can easily find Isc. Also note that the 1mA source is connected in parallel with a short-circuited wire.

3. Sep 12, 2008

john88

Re: thevenin

so if short circuit the system. Can I setup KCL on node A and then solve for I,
I = I(source) + I(R10).

But it seems odd to do so.

4. Sep 12, 2008

Defennder

Re: thevenin

You got the equation wrong. It's IR10 = Isource + I. Be careful of the direction designated for Isc.

5. Sep 16, 2008

john88

Re: thevenin

ok, got everything together now, ty for the help!