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## Homework Statement

A variable resistor (RL) is connected to an unknown circuit. It is found that the

maximum power that can be dissipated in the resistor (RL) is 10W, and that this

occurs when the value of the resistor (RL) is 25ohms.

Derive the Thevenin equivalent circuit for the unknown circuit, and hence find the

current which flows when RL = 5ohms.

## Homework Equations

Maximum power dissaption occurs when RL=RS which was 25ohm

Which means P=V^2/R= V=sqrootof P*R = sqrootof 10W*(25+25)ohms=22.4V

Equivalent circuit is a 22.4 V power supply and a 25 ohm resistor

When RL is 5 I=V/(Rs+RL)=22.4/(25+5)=0.74Amps

are my calculations correct?