A variable resistor (RL) is connected to an unknown circuit. It is found that the
maximum power that can be dissipated in the resistor (RL) is 10W, and that this
occurs when the value of the resistor (RL) is 25ohms.
Derive the Thevenin equivalent circuit for the unknown circuit, and hence find the
current which flows when RL = 5ohms.
Maximum power dissaption occurs when RL=RS which was 25ohm
Which means P=V^2/R= V=sqrootof P*R = sqrootof 10W*(25+25)ohms=22.4V
Equivalent circuit is a 22.4 V power supply and a 25 ohm resistor
When RL is 5 I=V/(Rs+RL)=22.4/(25+5)=0.74Amps
are my calculations correct?