Determine the Thevenin equivalent with respect to the terminals a,b
The Attempt at a Solution
I'm doing this practice problem and I calculated the the short circuit current below:
500uA*100ohm/(100ohm+1310ohm)= 35.460 uA
since 80*ib=current in v2, 35.460 A * 80=2836.87 uA
Now for the open circuit voltage..
80ib* 50kohm= 40.0*10^5 ib
Now to solve for ib is where I'm lost.
In the solution they have 4*10^-5v2=-160ib, but I have no idea where it came from?