1. The problem statement, all variables and given/known data Determine the Thevenin equivalent with respect to the terminals a,b 2. Relevant equations Rth=Voc/Isc 3. The attempt at a solution I'm doing this practice problem and I calculated the the short circuit current below: 500uA*100ohm/(100ohm+1310ohm)= 35.460 uA since 80*ib=current in v2, 35.460 A * 80=2836.87 uA So Isc=2836.87 Now for the open circuit voltage.. 80ib* 50kohm= 40.0*10^5 ib Now to solve for ib is where I'm lost. In the solution they have 4*10^-5v2=-160ib, but I have no idea where it came from?