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## Homework Statement

Determine the Thevenin equivalent with respect to the terminals a,b

## Homework Equations

Rth=Voc/Isc

## The Attempt at a Solution

I'm doing this practice problem and I calculated the the short circuit current below:

500uA*100ohm/(100ohm+1310ohm)= 35.460 uA

since 80*ib=current in v2, 35.460 A * 80=2836.87 uA

So Isc=2836.87

Now for the open circuit voltage..

80ib* 50kohm= 40.0*10^5 ib

Now to solve for ib is where I'm lost.

In the solution they have 4*10^-5v2=-160ib, but I have no idea where it came from?