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Thevenin equivalent question
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[QUOTE="orangeincup, post: 4996941, member: 518656"] [h2]Homework Statement [/h2] Determine the Thevenin equivalent with respect to the terminals a,b [h2]Homework Equations[/h2] Rth=Voc/Isc [h2]The Attempt at a Solution[/h2] I'm doing this practice problem and I calculated the the short circuit current below: 500uA*100ohm/(100ohm+1310ohm)= 35.460 uA since 80*ib=current in v2, 35.460 A * 80=2836.87 uA So Isc=2836.87 Now for the open circuit voltage.. 80ib* 50kohm= 40.0*10^5 ib Now to solve for ib is where I'm lost. In the solution they have 4*10^-5v2=-160ib, but I have no idea where it came from? [/QUOTE]
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Thevenin equivalent question
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