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Thevenin Equivalent

  • Thread starter qwerty2x
  • Start date
  • #1
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Homework Statement




Find the Thevenin Equivalent resistance for the network below:
http://img27.imageshack.us/img27/8508/circuit.png [Broken]


Homework Equations



R=(1/R1+1/R2)^-1


The Attempt at a Solution



Hi all,

to find the resistance i short circuited the volage sources and created an open loop across the current source. Then it looks like the current will not travel through the uppr loop beacuse its in parallel with a short circuit(where the current will rather go). I concluded that by breaking the circuit at Vo we have R1 and R2 in parallel. Which leaves us with the resistance being 2.7K ohm. but thats incorrect according to my book.

Help appreciated thnks
 
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Answers and Replies

  • #2
G01
Homework Helper
Gold Member
2,665
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You removed the sources in the correct way, but I'll need to see your calculations if I am going to be able to see your mistake. Can you show your calculations? Also, what do you mean by R_1 and R_2? There are five resistors, not just two.
 
Last edited:
  • #3
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thanks for the reply,

resistance=((1/8.3k)+(1/4.1k))^-1 (just 2 resistors in parallel)
so resistance is 2.74kOhms
 
  • #4
Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
12,098
129
The 2 resistors in the top half of the circuit are not in parallel (after removing the current source and shorting the voltage sources).

Note, the resistance is to be calculated across the + and - terminals of Vo.
 

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