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Never mind, did superposition incorrectly.

http://img258.imageshack.us/img258/9206/jesus2gn2.th.png [Broken]

Find Vload using superposition and thevenin's equivalent

Well for network on the left of Rload, I found Vth = 5 V and Rth = 15.1 kohms

For the network on the right of Rload, I found Vth = 7.5 V and Rth = 8150 ohms.

So using superposition I would do:

1) 5 V * 10k / (10k+15.1k) = 1.99 V on Rload

2) 7.5 V * 10k / (10k + 8150) = 4.13 V

Adding those I get 6.12 V.

However, when I simulate this in PSPICE I get 4.33 V.

I also checked each side and I get 1.99 V on the left (when I disconnect the right) and I get 4.13 V on the right (when I disconnect the left).

What am I doing wrong, I can't even remotely see where that 4.33 V comes from.

**1. Homework Statement**http://img258.imageshack.us/img258/9206/jesus2gn2.th.png [Broken]

Find Vload using superposition and thevenin's equivalent

**2. Homework Equations****3. The Attempt at a Solution**Well for network on the left of Rload, I found Vth = 5 V and Rth = 15.1 kohms

For the network on the right of Rload, I found Vth = 7.5 V and Rth = 8150 ohms.

So using superposition I would do:

1) 5 V * 10k / (10k+15.1k) = 1.99 V on Rload

2) 7.5 V * 10k / (10k + 8150) = 4.13 V

Adding those I get 6.12 V.

However, when I simulate this in PSPICE I get 4.33 V.

I also checked each side and I get 1.99 V on the left (when I disconnect the right) and I get 4.13 V on the right (when I disconnect the left).

What am I doing wrong, I can't even remotely see where that 4.33 V comes from.

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