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Thevenin's Theorem question

  1. Oct 28, 2010 #1
    1. The problem statement, all variables and given/known data

    [PLAIN]http://img21.imageshack.us/img21/2408/screenshot20101028at112.png [Broken]

    Hi,

    I'm new to these forums, so hopefully this is the right place to post this question. I need some help in the question above. I'm not obtaining the right answer for this question and I'm not too sure whether my working out is correct as there there are no worked solutions for this question. If anyone can provide me some steps to solve this question, it will be greatly appreciated.

    Thanks in advance.

    Daniel
     
    Last edited by a moderator: May 5, 2017
  2. jcsd
  3. Oct 28, 2010 #2
    Okay, fortunately I've found the worked solutions for this question in my portal. But I still do not understand this part of the solution:

    [PLAIN]http://img507.imageshack.us/img507/6680/screenshot20101028at115.png [Broken]

    I know that we are using superposition, but I do not understand how they got the values for the voltage division. Why is the 12k Ohm resistor used in the numerator? Like why does the voltage drop across the 12k ohm resistor equate to Voc'? And in the denominator, which 2k ohm resistor are they referring to? And why is the other 2k ohm ignored?

    Thanks in advance
     
    Last edited by a moderator: May 5, 2017
  4. Oct 30, 2010 #3

    CEL

    User Avatar

    There is no current through the upper 2k resistor, so no voltage drop. You can substitute it by a short circuit. In this way Voc is the voltage across the 12k resistor.
     
  5. Oct 30, 2010 #4
    Thanks. Got it now.
     
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