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Homework Help: Thevenin's Theorem

  1. Nov 17, 2017 #181
    Ahhh! Thank you! I was able to transpose that equation for VTh and ended up with the answer I was expecting.

    Thanks again.
  2. Jan 8, 2018 #182
    I am currently on part c) and have converted each voltage source and series impedance into a current source and parallel impedance using Ohms Law, I = V/Z which i get 103.75 for v1 and -J69.17 for v2.
    Then combining them to get 103.75-j69.17 as my voltage source.
    Then to combine J4 and J6 which are in parallel which i make j2.4.

    The next bit i'm slightly confused on which is to use current divider rule to calculate the load current which i think is Ix=[Rt/(Rt+Rx)]*It
    It= the current source. Please can advise me if i'm on the right track.
  3. Jan 8, 2018 #183


    User Avatar

    Staff: Mentor

    I think you mean current source. You added the two Norton sources.
    Yes, you're on the right track.
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