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Thin Film interference

  • Thread starter Joza
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  • #1
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A thin film is put on the surface of glass, with indexes of refraction of x and y respectively.

If light, with wavelength L in air, is reflected from the 2 sides of the film, to interfere constructively, what is the minimum thickness required.


The question is stated just like that, so I think it is vague in some parts.

I can't think of a formula to work this out. I know for con. interference, 2t=mL, where m is a whole number. But this isn't enough, and doesn't relate the indexes of r.

Any hints????
 

Answers and Replies

  • #2
Shouldn't be doing your Homework 3 and half hours before its due.. tut tut:tongue2:
 
  • #3
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Haha. I'd usually do it on Saturday, but with a boozin session going down, it didnt get done.

Besides, I'm a member here ages, so the guys can be great help when needed.

So did you get this one???? Hey I helped you with the polarizer one :approve:
 
  • #4
Sure i got it......................

Nah i think i'm retarded, on 40%..

Still can't get the polarizer one or this one or the last one lol
 
  • #5
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Ah....there would have been a nice a pav pint in it for ya.

Hey, what's your name? Don't tell me your TP.....:rolleyes:
 
  • #6
Im taking a break, think "Fringes from Different Interfering Wavelengths" may be answerable! If i hit 60 i'll be proud! lol ;)
 
  • #7
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I don't think I'll hit 60 this time....


Damn weekends....;)
 
  • #8
Doc Al
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I can't think of a formula to work this out. I know for con. interference, 2t=mL, where m is a whole number. But this isn't enough, and doesn't relate the indexes of r.
Assuming x < y, the phase change on reflection is the same for both reflections so all that matters is the phase difference due to traveling through the film. That equation (2t = mL) will work, but L must be the wavelength in the film. That's where the index of refraction comes in.

If x > y, things will be a bit different. Learn more here: http://hyperphysics.phy-astr.gsu.edu/hbase/phyopt/thinfilm.html" [Broken]
 
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  • #9
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Yes, x > y.

I understand it when x < y.

Then 2t=L, where L is wavelength in the film. So L would be index of refraction in film times wavelength in air.

But x > y.....
 
  • #10
Doc Al
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Yes, x > y.

I understand it when x < y.

Then 2t=L, where L is wavelength in the film. So L would be index of refraction in film times wavelength in air.
Not exactly. Is the wavelength shorter or longer in the film?

But x > y.....
In that case the second reflection undergoes a different phase shift than the first (actually no phase shift). See that link for details.
 
  • #11
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Sorry, divided by.....

So does that mean 2t=L?? Or t=L?
 
  • #12
Doc Al
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So does that mean 2t=L?? Or t=L?
When x > y, the condition for constructive interference (and minimum thickness) is 2t = L/2 (where L = wavelength in the film).
 

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